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Class 12 Differential Equations · Very Long Answer5 Markshomogeneous_differential_equations

Class 12 Maths · Differential Equations · Very Long Answer #72

Show that (xe^(y/x) + y)dx = xdy is homogeneous and solve it with y(1) = 1.

✅ Step-by-Step Solution

Final Answer: e^(−y/x) + ln x = 1/e; y = −x ln(1/e − ln x), 0 < x < e^(1/e).
  1. Write y′ = e^(y/x) + y/x. This depends only on y/x and is homogeneous.
  2. Put v = y/x. Then v + xv′ = eᵛ + v, so e^(−v)dv = dx/x.
  3. Integrating gives −e^(−v) = ln|x| + C.
  4. At (1, 1), C = −1/e. Thus e^(−y/x) = 1/e − ln x.
  5. Therefore y = −x ln(1/e − ln x), on 0 < x < e^(1/e), where the logarithm argument is positive.

📋 CBSE Stepwise Marking Scheme

  • [1 mark] Write y′ = e^(y/x) + y/x. This depends only on y/x and is homogeneous.
  • [1 mark] Put v = y/x. Then v + xv′ = eᵛ + v, so e^(−v)dv = dx/x.
  • [1 mark] Integrating gives −e^(−v) = ln|x| + C.
  • [1 mark] At (1, 1), C = −1/e. Thus e^(−y/x) = 1/e − ln x.
  • [1 mark] Therefore y = −x ln(1/e − ln x), on 0 < x < e^(1/e), where the logarithm argument is positive.

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