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Class 12 Differential Equations · Very Long Answer5 Markslinear_differential_equations

Class 12 Maths · Differential Equations · Very Long Answer #111

Solve dx/dy + x cot y = 2y + y²cot y, y ≠ 0, with x = 0 when y = π/2.

✅ Step-by-Step Solution

Final Answer: x sin y = y²sin y − π²/4, on 0 < y < π.
  1. This is linear in x(y), with P = cot y. A convenient IF is sin y.
  2. Then d(x sin y)/dy = 2y sin y + y²cos y.
  3. The right side is d(y²sin y)/dy, so x sin y = y²sin y + C.
  4. At y = π/2 and x = 0, C = −π²/4.
  5. Thus x sin y = y²sin y − π²/4, on (0, π), where cot y is defined.

📋 CBSE Stepwise Marking Scheme

  • [1 mark] This is linear in x(y), with P = cot y. A convenient IF is sin y.
  • [1 mark] Then d(x sin y)/dy = 2y sin y + y²cos y.
  • [1 mark] The right side is d(y²sin y)/dy, so x sin y = y²sin y + C.
  • [1 mark] At y = π/2 and x = 0, C = −π²/4.
  • [1 mark] Thus x sin y = y²sin y − π²/4, on (0, π), where cot y is defined.

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