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Class 12 Differential Equations · Long Answer3 Markshomogeneous_differential_equations

Class 12 Maths · Differential Equations · Long Answer #97

Solve (x² + 3xy + y²)dx − x²dy = 0, y(1) = 0.

✅ Step-by-Step Solution

Final Answer: y = x ln x/(1 − ln x), 0 < x < e.
  1. For x ≠ 0 put v = y/x. Then v + xv′ = 1 + 3v + v², giving xv′ = (1 + v)².
  2. Near v = 0, integrate dv/(1 + v)² = dx/x to get −1/(1 + v) = ln|x| + C.
  3. At (1, 0), C = −1. Hence 1/(1 + v) = 1 − ln x.
  4. Therefore y = x ln x/(1 − ln x), on (0, e), the maximal interval through 1.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] For x ≠ 0 put v = y/x. Then v + xv′ = 1 + 3v + v², giving xv′ = (1 + v)².
  • [1 mark] Near v = 0, integrate dv/(1 + v)² = dx/x to get −1/(1 + v) = ln|x| + C.
  • [1 mark] At (1, 0), C = −1. Hence 1/(1 + v) = 1 − ln x.
  • [0.5 marks] Therefore y = x ln x/(1 − ln x), on (0, e), the maximal interval through 1.

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