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Class 12 Differential Equations · Long Answer3 Markslinear_differential_equations

Class 12 Maths · Differential Equations · Long Answer #54

Solve y′ + 2y tan x = sin x, y(π/3) = 0.

✅ Step-by-Step Solution

Final Answer: y = cos x − 2cos²x, −π/2 < x < π/2.
  1. An integrating factor is exp(∫2tan x dx) = sec²x.
  2. Then (y sec²x)′ = sin x sec²x = (sec x)′. Integrating yields y sec²x = sec x + C.
  3. At x = π/3, y = 0 and sec x = 2, so C = −2.
  4. Thus y = cos x − 2cos²x on the interval (−π/2, π/2).

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] An integrating factor is exp(∫2tan x dx) = sec²x.
  • [1 mark] Then (y sec²x)′ = sin x sec²x = (sec x)′. Integrating yields y sec²x = sec x + C.
  • [1 mark] At x = π/3, y = 0 and sec x = 2, so C = −2.
  • [0.5 marks] Thus y = cos x − 2cos²x on the interval (−π/2, π/2).

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