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Class 12 Integrals · Very Long Answer5 Marksindefinite_integration

Class 12 Maths · Integrals · Very Long Answer #108

Evaluate \(\int \frac{2 x}{\left(x^{2} + 1\right) \left(x^{2} + 3\right)}\,dx\). Work on each connected open interval where the real integrand is defined.

✅ Step-by-Step Solution

Final Answer: \(\frac{\log{\left(\frac{x^{2} + 1}{x^{2} + 3} \right)}}{2}\) + C
  1. Set u=x², du=2x dx.
  2. The integral becomes ∫du/[(u+1)(u+3)]. Set this fraction equal to A/(u+1)+B/(u+3).
  3. Equate 1=(A+B)u+3A+B. Thus A+B=0 and 3A+B=1, giving A=1/2,B=−1/2.
  4. Integrate to (1/2)ln|u+1|−(1/2)ln|u+3| and substitute u=x²; both arguments are positive.
  5. Therefore the required integral is \(\frac{\log{\left(\frac{x^{2} + 1}{x^{2} + 3} \right)}}{2}\) + C.

📋 CBSE Stepwise Marking Scheme

  • [1 mark] Set u=x², du=2x dx.
  • [1 mark] The integral becomes ∫du/[(u+1)(u+3)]. Set this fraction equal to A/(u+1)+B/(u+3).
  • [1 mark] Equate 1=(A+B)u+3A+B. Thus A+B=0 and 3A+B=1, giving A=1/2,B=−1/2.
  • [1 mark] Integrate to (1/2)ln|u+1|−(1/2)ln|u+3| and substitute u=x²; both arguments are positive.
  • [1 mark] Therefore the required integral is \(\frac{\log{\left(\frac{x^{2} + 1}{x^{2} + 3} \right)}}{2}\) + C.

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