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Class 12 Integrals · Very Long Answer5 Marksdefinite_integration

Class 12 Maths · Integrals · Very Long Answer #177

Evaluate the convergent improper integral \(\int_0^{\pi/4}dx/[\cos^3x\sqrt{2\sin2x}]\).

✅ Step-by-Step Solution

Final Answer: 6/5
  1. For 0<x≤π/4, √(2sin2x)=2cos x√(tan x), since cosine is positive.
  2. Thus I=(1/2)∫₀^(π/4)sec⁴x/√(tan x)dx. Set u=tan x, du=sec²x dx; the limits become 0,1.
  3. Using sec²x=1+u², the transformed integral is (1/2)∫₀¹[u^(−1/2)+u^(3/2)]du. Both powers are integrable at zero.
  4. Its primitive is √u+u^(5/2)/5. Evaluate the limiting lower endpoint 0 and upper endpoint 1.
  5. Therefore the integral equals 6/5.

📋 CBSE Stepwise Marking Scheme

  • [1 mark] For 0<x≤π/4, √(2sin2x)=2cos x√(tan x), since cosine is positive.
  • [1 mark] Thus I=(1/2)∫₀^(π/4)sec⁴x/√(tan x)dx. Set u=tan x, du=sec²x dx; the limits become 0,1.
  • [1 mark] Using sec²x=1+u², the transformed integral is (1/2)∫₀¹[u^(−1/2)+u^(3/2)]du. Both powers are integrable at zero.
  • [1 mark] Its primitive is √u+u^(5/2)/5. Evaluate the limiting lower endpoint 0 and upper endpoint 1.
  • [1 mark] Therefore the integral equals 6/5.

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