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Class 12 Integrals · Long Answer3 Marksindefinite_integration

Class 12 Maths · Integrals · Long Answer #81

Evaluate \(\int \frac{\left(3 \sin{\left(x \right)} - 2\right) \cos{\left(x \right)}}{- 4 \sin{\left(x \right)} - \cos^{2}{\left(x \right)} + 5}\,dx\). Work on each connected open interval where the real integrand is defined.

✅ Step-by-Step Solution

Final Answer: \(3 \log{\left(2 - \sin{\left(x \right)} \right)} - \frac{4}{\sin{\left(x \right)} - 2}\) + C
  1. Set u=sin x, du=cos x dx. The denominator becomes 5−(1−u²)−4u=(u−2)².
  2. Now (3u−2)/(u−2)²=3/(u−2)+4/(u−2)².
  3. Integrating gives 3ln|u−2|−4/(u−2); substitute u=sin x, noting |sin x−2|=2−sin x.
  4. Therefore the required integral is \(3 \log{\left(2 - \sin{\left(x \right)} \right)} - \frac{4}{\sin{\left(x \right)} - 2}\) + C.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Set u=sin x, du=cos x dx. The denominator becomes 5−(1−u²)−4u=(u−2)².
  • [1 mark] Now (3u−2)/(u−2)²=3/(u−2)+4/(u−2)².
  • [1 mark] Integrating gives 3ln|u−2|−4/(u−2); substitute u=sin x, noting |sin x−2|=2−sin x.
  • [0.5 marks] Therefore the required integral is \(3 \log{\left(2 - \sin{\left(x \right)} \right)} - \frac{4}{\sin{\left(x \right)} - 2}\) + C.

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