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Class 12 Integrals · Short Answer2 Marksindefinite_integration

Class 12 Maths · Integrals · Short Answer #45

Evaluate \(\int \frac{1}{x^{2} - 6 x + 13}\,dx\). Work on each connected open interval where the real integrand is defined.

✅ Step-by-Step Solution

Final Answer: \(\frac{\operatorname{atan}{\left(\frac{x}{2} - \frac{3}{2} \right)}}{2}\) + C
  1. Complete the square: x²−6x+13=(x−3)²+4.
  2. Use u=(x−3)/2, dx=2du, giving (1/2)∫du/(1+u²)=(1/2)arctan u+C.
  3. Therefore the required integral is \(\frac{\operatorname{atan}{\left(\frac{x}{2} - \frac{3}{2} \right)}}{2}\) + C.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Complete the square: x²−6x+13=(x−3)²+4.
  • [1 mark] Use u=(x−3)/2, dx=2du, giving (1/2)∫du/(1+u²)=(1/2)arctan u+C.
  • [0.5 marks] Therefore the required integral is \(\frac{\operatorname{atan}{\left(\frac{x}{2} - \frac{3}{2} \right)}}{2}\) + C.

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