Class 12 Inverse Trigonometric Functions · Short Answer2 Marksprincipal_values
Class 12 Maths · Inverse Trigonometric Functions · Short Answer #44
Evaluate \(\sin^{-1}[\sin(13\pi/7)]\).
✅ Step-by-Step Solution
Final Answer: −π/7
- Use 13π/7=2π−π/7 and sine periodicity.
- sin(13π/7)=sin(−π/7), where −π/7∈[−π/2,π/2].
- Therefore the principal arcsine is −π/7.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use 13π/7=2π−π/7 and sine periodicity.
- [1 mark] sin(13π/7)=sin(−π/7), where −π/7∈[−π/2,π/2].
- [0.5 marks] Therefore the principal arcsine is −π/7.
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