Class 12 Matrices · Short Answer2 Marksmatrix_polynomials
Class 12 Maths · Matrices · Short Answer #97
For A=\(\begin{bmatrix}2 & -2\\-2 & 2\end{bmatrix}\), find p such that A²=pA.
✅ Step-by-Step Solution
Final Answer: p=4
- Multiplication gives A²=[[8,−8],[−8,8]].
- This equals 4A, and the nonzero first entry gives the unique scalar p=4.
- Thus p=4.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Multiplication gives A²=[[8,−8],[−8,8]].
- [1 mark] This equals 4A, and the nonzero first entry gives the unique scalar p=4.
- [0.5 marks] Thus p=4.
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