Class 12 Vector Algebra · Conceptual Answer1 Marksorthogonality
Class 12 Maths · Vector Algebra · Conceptual Answer #93
Find a vector of magnitude √171 perpendicular to (1,2,−3) and (3,−1,2).
✅ Step-by-Step Solution
Final Answer: (1,−11,−7), or its negative
- The cross product is (1,−11,−7), with squared norm 1+121+49=171. It has the required magnitude and perpendicularity.
- (1,−11,−7), or its negative
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The cross product is (1,−11,−7), with squared norm 1+121+49=171. It has the required magnitude and perpendicularity.
- [0.5 marks] (1,−11,−7), or its negative
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