Class 12 Vector Algebra · Short Answer2 Markssection_formula
Class 12 Maths · Vector Algebra · Short Answer #47
A point on the line through P = (2,2,1) and Q = (5,1,−2) has x-coordinate 4. Find its z-coordinate.
✅ Step-by-Step Solution
Final Answer: z = −1.
- Write R = P + t(Q − P), where Q − P = (3,−1,−3).
- Its x-coordinate gives 2 + 3t = 4, so t = 2/3. Its z-coordinate is 1 − 3t.
- Thus z = 1 − 2 = −1.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Write R = P + t(Q − P), where Q − P = (3,−1,−3).
- [1 mark] Its x-coordinate gives 2 + 3t = 4, so t = 2/3. Its z-coordinate is 1 − 3t.
- [0.5 marks] Thus z = 1 − 2 = −1.
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