Class 12 Vector Algebra · Short Answer2 Marksorthogonality
Class 12 Maths · Vector Algebra · Short Answer #56
Find all vectors of magnitude 6 perpendicular to both (2,−1,2) and (4,−1,3).
✅ Step-by-Step Solution
Final Answer: ±(−2,4,4).
- The cross product is (−1,2,2), of norm 3.
- The only perpendicular directions are ±(−1,2,2)/3. Multiply each by 6.
- The required vectors are ±(−2,4,4).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The cross product is (−1,2,2), of norm 3.
- [1 mark] The only perpendicular directions are ±(−1,2,2)/3. Multiply each by 6.
- [0.5 marks] The required vectors are ±(−2,4,4).
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