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Class 12 Vector Algebra · Short Answer2 Marksvector_identities

Class 12 Maths · Vector Algebra · Short Answer #58

Prove |a × b|² = |a|²|b|² − (a · b)² for any vectors a,b.

✅ Step-by-Step Solution

Final Answer: |a × b|² = |a|²|b|² − (a · b)².
  1. If either vector is zero, both sides vanish. Otherwise let θ be their angle.
  2. Use a · b = |a||b|cos θ and |a × b| = |a||b|sin θ. Then |a|²|b|² − (a · b)² = |a|²|b|²(1 − cos²θ) = |a|²|b|²sin²θ.
  3. This equals |a × b|², completing the proof including zero-vector cases.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] If either vector is zero, both sides vanish. Otherwise let θ be their angle.
  • [1 mark] Use a · b = |a||b|cos θ and |a × b| = |a||b|sin θ. Then |a|²|b|² − (a · b)² = |a|²|b|²(1 − cos²θ) = |a|²|b|²sin²θ.
  • [0.5 marks] This equals |a × b|², completing the proof including zero-vector cases.

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