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NCERT Class 12 · Ch 8 Miscellaneous Exercise · Q2

NCERT Class 12 Maths · Chapter 8 Applications Of Integrals · Miscellaneous Exercise Question 2

Sketch y=|x+3| and evaluate ∫₋₆⁰|x+3| dx.
Absolute-value graph: y = |x+3|
Absolute-value graph: y = |x+3|

💡 Concept Hints

  1. Sketch the region, choose a vertical or horizontal strip, and find all sign changes.
  2. Express its area as an integral of upper minus lower (or right minus left), splitting where necessary.

✅ Step-by-Step Solution

Final Answer: 9.
  1. The graph is a V with vertex (−3,0); y=−x−3 for x≤−3 and y=x+3 for x≥−3.
  2. Split at x=−3: I=∫₋₆⁻³(−x−3)dx+∫₋₃⁰(x+3)dx.
  3. The first integral [−x²/2−3x]₋₆⁻³=9/2. The second [x²/2+3x]₋₃⁰=9/2.
  4. Thus I=9. Geometrically these are two triangles, each base 3 and height 3.

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