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NCERT Class 12 · Ch 5 Exercise 5.2 · Q5

NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.2 Question 5

Differentiate \(\frac{\sin{\left(a x + b \right)}}{\cos{\left(c x + d \right)}}\) with respect to x; where the denominator cos(cx+d) is nonzero.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(\frac{a \cos{\left(a x + b \right)} + \frac{c \sin{\left(a x + b \right)} \sin{\left(c x + d \right)}}{\cos{\left(c x + d \right)}}}{\cos{\left(c x + d \right)}}\)
  1. Work where the denominator cos(cx+d) is nonzero.
  2. Product rule: differentiate each variable factor once, keeping the other factors unchanged. Here \(\frac{\partial}{\partial x} \frac{\sin{\left(a x + b \right)}}{\cos{\left(c x + d \right)}}\) = \(\frac{a \cos{\left(a x + b \right)}}{\cos{\left(c x + d \right)}} + \frac{c \sin{\left(a x + b \right)} \sin{\left(c x + d \right)}}{\cos^{2}{\left(c x + d \right)}}\).
  3. Combining the terms gives y′ = \(\frac{a \cos{\left(a x + b \right)} + \frac{c \sin{\left(a x + b \right)} \sin{\left(c x + d \right)}}{\cos{\left(c x + d \right)}}}{\cos{\left(c x + d \right)}}\).

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