NCERT Class 12 · Ch 5 Exercise 5.7 · Q15
NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.7 Question 15
If y=\(500 e^{7 x} + 600 e^{- 7 x}\), show y″=49y.
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: y″=49y
- First derivative: y′=\(3500 e^{7 x} - 4200 e^{- 7 x}\).
- Second derivative: y″=\(4900 \left(5 e^{7 x} + 6 e^{- 7 x}\right)\).
- Substitution into the indicated left-hand combination and simplification gives \(0\).
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