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NCERT Class 12 · Ch 4 Exercise 4.2 · Q1

NCERT Class 12 Maths · Chapter 4 Determinants · Exercise 4.2 Question 1

Find the triangle areas for (i) (1,0),(6,0),(4,3); (ii) (2,7),(1,1),(10,8); (iii) (−2,−3),(3,2),(−1,−8).
Triangle 1
Triangle 1
Triangle 2
Triangle 2
Triangle 3
Triangle 3

💡 Concept Hints

  1. Identify whether this needs determinant expansion, an inverse, or the absolute determinant formula for area.
  2. For a determinant use signed cofactors. For a system first check invertibility; for an area take half the absolute determinant.

✅ Step-by-Step Solution

Final Answer: (i) \(\frac{15}{2}\); (ii) \(\frac{47}{2}\); (iii) \(15\) square units.
  1. Part 1: use Δ=½|det \(\left[\begin{matrix}1 & 0 & 1\\6 & 0 & 1\\4 & 3 & 1\end{matrix}\right]\)|.
  2. Expand the determinant along row 1, using cofactors Cᵢⱼ=(−1)ⁱ⁺ʲMᵢⱼ.
  3. The cofactors in this row are \(\left[\begin{matrix}-3 & -2 & 18\end{matrix}\right]\).
  4. The expansion terms are \(-3\), \(0\), \(18\).
  5. Adding and simplifying gives det A = \(15\).
  6. The area is \(\frac{15}{2}\) square units.
  7. Part 2: use Δ=½|det \(\left[\begin{matrix}2 & 7 & 1\\1 & 1 & 1\\10 & 8 & 1\end{matrix}\right]\)|.
  8. Expand the determinant along row 1, using cofactors Cᵢⱼ=(−1)ⁱ⁺ʲMᵢⱼ.
  9. The cofactors in this row are \(\left[\begin{matrix}-7 & 9 & -2\end{matrix}\right]\).
  10. The expansion terms are \(-14\), \(63\), \(-2\).
  11. Adding and simplifying gives det A = \(47\).
  12. The area is \(\frac{47}{2}\) square units.
  13. Part 3: use Δ=½|det \(\left[\begin{matrix}-2 & -3 & 1\\3 & 2 & 1\\-1 & -8 & 1\end{matrix}\right]\)|.
  14. Expand the determinant along row 1, using cofactors Cᵢⱼ=(−1)ⁱ⁺ʲMᵢⱼ.
  15. The cofactors in this row are \(\left[\begin{matrix}10 & -4 & -22\end{matrix}\right]\).
  16. The expansion terms are \(-20\), \(12\), \(-22\).
  17. Adding and simplifying gives det A = \(-30\).
  18. The area is \(15\) square units.

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