NCERT Class 12 · Ch 9 Exercise 9.1 · Q4
NCERT Class 12 Maths · Chapter 9 Differential Equations · Exercise 9.1 Question 4
Determine order and degree of (y″)²+cos(y′)=0.
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: Order 2; degree not defined.
- The highest derivative appearing is of order 2.
- A trigonometric function of a derivative prevents polynomial dependence on derivatives, so degree is undefined.
Master Chapter 9: Differential Equations
Practise interactive questions, flashcards, visual mind maps, and timed board tests for Differential Equations.
← Previous Question
Determine order and degree of (ds/dt)⁴+3s·d²s/dt²=0.
Next Question →Determine order and degree of y″=cos 3x+sin 3x.
Related Questions in Differential Equations
Class 12 Differential Equations · Mcq Single Correct
Find the degree of x²y″ = (xy′ − y)³.
Class 12 Differential Equations · Mcq Single Correct
Find the degree of y″ + 3(y′)² = x² ln(y″).
Class 12 Differential Equations · Mcq Single Correct
Find the order and degree of [1 + (y′)²]² = y″.
Class 12 Differential Equations · Mcq Single Correct
The nonconstant solutions of 2xy′ − y = 3 lie on a family of which curves?
Class 12 Differential Equations · Mcq Single Correct
Find an integrating factor of (x ln x)y′ + y = 2 ln x, for x > 0, x ≠ 1.
Class 12 Differential Equations · Mcq Single Correct
Which function satisfies (y′)² − xy′ + y = 0?