Mathbee CBSE Mathbee · CBSE Class 12 Maths
NCERT Class 12 · Ch 2 Miscellaneous Exercise · Q13

NCERT Class 12 Maths · Chapter 2 Inverse Trigonometric Functions · Miscellaneous Exercise Question 13

For |x|<1, evaluate sin(tan⁻¹x).

💡 Concept Hints

  1. Recall the principal range of the inverse function before simplifying.
  2. Find an angle with the required trigonometric value, then verify it belongs to the principal range.

✅ Step-by-Step Solution

Final Answer: D: x/√(1+x²).
  1. Set θ=tan⁻¹x∈(−π/2,π/2), so cos θ>0.
  2. Then cos θ=1/√(1+x²) and sin θ=tan θ cos θ=x/√(1+x²). Select D.

Master Chapter 2: Inverse Trigonometric Functions

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Inverse Trigonometric Functions.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
Solve tan⁻¹((1−x)/(1+x))=(1/2)tan⁻¹x, x>0.
Next Question →
Solve sin⁻¹(1−x)−2sin⁻¹x=π/2.

All Questions in Inverse Trigonometric Functions — Miscellaneous Exercise

Related Questions in Inverse Trigonometric Functions