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Class 12 Three Dimensional Geometry · Very Long Answer5 Marksangles_between_lines

Class 12 Maths · Three Dimensional Geometry · Very Long Answer #91

Find the acute angles between (i) (x−2)/2=(y−1)/5=(z+3)/(−3) and (x+2)/(−1)=(y−4)/8=(z−5)/4; (ii) x/2=y/2=z and (x−5)/4=(y−2)= (z−3)/8.

✅ Step-by-Step Solution

Final Answer: (i) cos⁻¹(26/(9√38)); (ii) cos⁻¹(2/3).
  1. Use cos θ=|d·e|/(|d||e|) for the acute line angle.
  2. In (i), d=(2,5,−3),e=(−1,8,4), with dot product 26.
  3. Their norms are √38 and 9, giving cos θ₁=26/(9√38).
  4. In (ii), d=(2,2,1),e=(4,1,8), with dot product 18 and norms 3 and 9.
  5. Thus θ₁=cos⁻¹(26/(9√38)), θ₂=cos⁻¹(2/3).

📋 CBSE Stepwise Marking Scheme

  • [1 mark] Use cos θ=|d·e|/(|d||e|) for the acute line angle.
  • [1 mark] In (i), d=(2,5,−3),e=(−1,8,4), with dot product 26.
  • [1 mark] Their norms are √38 and 9, giving cos θ₁=26/(9√38).
  • [1 mark] In (ii), d=(2,2,1),e=(4,1,8), with dot product 18 and norms 3 and 9.
  • [1 mark] Thus θ₁=cos⁻¹(26/(9√38)), θ₂=cos⁻¹(2/3).

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