Class 12 Three Dimensional Geometry · Short Answer2 Marksdistance_to_origin
Class 12 Maths · Three Dimensional Geometry · Short Answer #37
Find points on x=(y−1)/2=(z+1)/2 at distance √11 from the origin.
✅ Step-by-Step Solution
Final Answer: (1,3,1) and (−1,−1,−3).
- Parametrize P(t)=(t,2t+1,2t−1).
- |P|²=t²+(2t+1)²+(2t−1)²=9t²+2=11, so t=±1.
- Substitution gives (1,3,1) and (−1,−1,−3).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Parametrize P(t)=(t,2t+1,2t−1).
- [1 mark] |P|²=t²+(2t+1)²+(2t−1)²=9t²+2=11, so t=±1.
- [0.5 marks] Substitution gives (1,3,1) and (−1,−1,−3).
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