Class 12 Three Dimensional Geometry · Long Answer3 Marksshortest_distance
Class 12 Maths · Three Dimensional Geometry · Long Answer #48
Find the shortest distance between r=(3,5,7)+t(1,-2,1), t∈ℝ and r=(-1,-1,-1)+t(7,-6,1), t∈ℝ.
✅ Step-by-Step Solution
Final Answer: 2*sqrt(29)
- For nonparallel lines use D=|(B−A)·(d×e)|/|d×e|.
- B−A=(-4,-6,-8), d×e=(4,6,8).
- The numerator is 116 and the denominator is 2*sqrt(29).
- Therefore D=2*sqrt(29).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] For nonparallel lines use D=|(B−A)·(d×e)|/|d×e|.
- [1 mark] B−A=(-4,-6,-8), d×e=(4,6,8).
- [1 mark] The numerator is 116 and the denominator is 2*sqrt(29).
- [0.5 marks] Therefore D=2*sqrt(29).
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