Class 12 Applications Of Derivatives · Mcq Single Correct1 Marksoptimization
Class 12 Maths · Applications Of Derivatives · Mcq Single Correct #20
Find the global minimum value of f(x)=x⁴−x²−2x+6.
✅ Step-by-Step Solution
Final Answer: Option (C): 4
- f′=2(x−1)(2x²+2x+1). The quadratic factor is always positive, so f decreases up to 1 and increases afterwards. f(1)=4.
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