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Class 12 Maths · Continuity And Differentiability · Case Study #35

A roller-coaster path is modeled by the polynomial f(x)=a(x+9)(x+1)(x−3). It crosses the y-axis at (0,−1). Use the mathematical model, rather than the indicative physical appearance, for the calculations.
Computed cubic graph consistent with roots −9,−1,3 and supplied y-intercept (0,−1). It is a mathematical path model, not a physical track scale.
Computed cubic graph consistent with roots −9,−1,3 and supplied y-intercept (0,−1). It is a mathematical path model, not a physical track scale.
Part (1) 2 Marks
Find a.
Answer: 1/27
  1. At x=0, f(0)=a·9·1·(−3)=−27a.
  2. Since f(0)=−1, −27a=−1 and a=1/27.
  3. Therefore a=1/27.
Part (2) 2 Marks
Find f″(1).
Answer: 20/27
  1. Expand the model using a=1/27: f(x)=(x³+7x²−21x−27)/27.
  2. Differentiate twice: f′(x)=(3x²+14x−21)/27 and f″(x)=(6x+14)/27.
  3. Thus f″(1)=(6+14)/27=20/27.

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