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Class 12 Continuity And Differentiability · Short Answer2 Markspiecewise_continuity

Class 12 Maths · Continuity And Differentiability · Short Answer #116

Examine continuity of f(x)=|x|+|x−1| at x=1.

✅ Step-by-Step Solution

Final Answer: Continuous at 1.
  1. For x near 1 on the left, f(x)=x+(1−x)=1; on the right, f(x)=x+(x−1)=2x−1.
  2. The left limit is 1, the right limit is 2·1−1=1, and f(1)=1.
  3. Both limits equal the value, so f is continuous at 1.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] For x near 1 on the left, f(x)=x+(1−x)=1; on the right, f(x)=x+(x−1)=2x−1.
  • [1 mark] The left limit is 1, the right limit is 2·1−1=1, and f(1)=1.
  • [0.5 marks] Both limits equal the value, so f is continuous at 1.

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