Mathbee CBSE Mathbee · CBSE Class 12 Maths
Class 12 Continuity And Differentiability · Short Answer2 Markssecond_derivatives

Class 12 Maths · Continuity And Differentiability · Short Answer #58

For y=√(ax+b) on any open interval where ax+b>0, prove yy″+(y′)²=0.

✅ Step-by-Step Solution

Final Answer: yy″+(y′)²=0
  1. Squaring gives y²=ax+b. Differentiation yields 2yy′=a.
  2. Differentiate again by the product rule: 2[(y′)²+yy″]=0.
  3. Divide by 2 to obtain yy″+(y′)²=0.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Squaring gives y²=ax+b. Differentiation yields 2yy′=a.
  • [1 mark] Differentiate again by the product rule: 2[(y′)²+yy″]=0.
  • [0.5 marks] Divide by 2 to obtain yy″+(y′)²=0.

Master Chapter 5: Continuity And Differentiability

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Continuity And Differentiability.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
For x=\(a \cos{\left(t \right)}\), y=\(b \sin{\left(t \right)}\)…
Next Question →
At x π/2 let f(x)=q(1−sin x)/(π−2x)². Find p,q for continuity at π/2.

More Practice Questions in Continuity And Differentiability

Related Questions in Continuity And Differentiability