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Class 12 Determinants · Mcq Single Correct1 Marksmatrix_inverse

Class 12 Maths · Determinants · Mcq Single Correct #20

For cosθ≠0, let \(\begin{bmatrix}1 & -\tan\theta\\\tan\theta & 1\end{bmatrix}\)\(\begin{bmatrix}1 & \tan\theta\\-\tan\theta & 1\end{bmatrix}\)⁻¹=\(\begin{bmatrix}a & −b\\b & a\end{bmatrix}\). Find a,b.

✅ Step-by-Step Solution

Final Answer: Option (B): a=cos2θ,b=sin2θ
  1. With t=tanθ, the inverse of [[1,t],[−t,1]] is [[1,−t],[t,1]]/(1+t²). The product is [[1−t²,−2t],[2t,1−t²]]/(1+t²). Thus a=cos2θ and b=sin2θ.

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