Class 12 Determinants · Conceptual Answer1 Marksminors_and_cofactors
Class 12 Maths · Determinants · Conceptual Answer #78
For \(\begin{vmatrix}2 & -3 & 5\\6 & 0 & 4\\1 & 5 & -7\end{vmatrix}\), let Aᵢⱼ be a cofactor. Find a₃₂A₃₂.
✅ Step-by-Step Solution
Final Answer: 110
- The entry a₃₂=5. Its cofactor is (−1)⁵det([[2,5],[6,4]])=−(8−30)=22, so the product is 5·22=110.
- 110
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The entry a₃₂=5. Its cofactor is (−1)⁵det([[2,5],[6,4]])=−(8−30)=22, so the product is 5·22=110.
- [0.5 marks] 110
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