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Class 12 Linear Programming · Case Study4 Markslinear_programming_models

Class 12 Maths · Linear Programming · Case Study #74

A dealer buys ceiling fans at ₹360 each and table fans at ₹240 each. Let their numbers be x,y, with x,y nonnegative integers. Storage holds at most 20 fans. For this model, take the available purchase budget as ₹5760. Profit is ₹22 per ceiling fan and ₹18 per table fan. Answer (i),(ii), and either (iii)(a) or (iii)(b).
Part (1) 1 Marks
Write the storage and purchase constraints.
Answer: x+y≤20; 360x+240y≤5760; x,y≥0 integers.
  1. Storage gives x+y≤20; purchase cost is 360x+240y.
  2. Thus 360x+240y≤5760, equivalently 3x+2y≤48, with nonnegative integer counts.
Part (2) 1 Marks
Write the profit objective.
Answer: Maximize Z=22x+18y.
  1. Multiply each fan count by its unit profit.
  2. Total profit is Z=22x+18y, to maximize.
Part (3) 2 Marks
Find the optimal numbers of fans.
Answer: 8 ceiling fans and 12 table fans.
  1. Relax to nonnegative real x,y and find vertices (0,0),(16,0),(8,12),(0,20).
  2. Profits are 0,352,392,360. The real optimum (8,12) is integral and meets both budget and storage limits.
  3. 8 ceiling fans and 12 table fans.
Part (4) 2 Marks
Find the maximum total profit.
Answer: ₹392.
  1. Relax to nonnegative real x,y and find vertices (0,0),(16,0),(8,12),(0,20).
  2. Profits are 0,352,392,360. The real optimum (8,12) is integral and meets both budget and storage limits.
  3. ₹392.

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