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Class 12 Linear Programming · Long Answer3 Marksgraphical_optimization

Class 12 Maths · Linear Programming · Long Answer #31

Maximize Z=3*x + 9*y subject to -x - y ≤ -10; x + 3*y ≤ 60; x - y ≤ 0; -x ≤ 0; -y ≤ 0. Solve graphically.
Coordinate-derived feasible-region graph for cbse12-math-lp-p1-short-005
Coordinate-derived feasible-region graph for cbse12-math-lp-p1-short-005

✅ Step-by-Step Solution

Final Answer: max Z=180 at (0,20), (15,15) and every point on their joining segment.
  1. Draw each boundary ax+by=c and retain the closed half-plane ax+by≤c; intersect all constraints, including x,y≥0.
  2. Solving pairs of boundary equations and rejecting points violating any inequality gives vertices: (0,10), (0,20), (5,5), (15,15).
  3. Evaluate the objective at every vertex: (0,10) → 90; (0,20) → 180; (5,5) → 60; (15,15) → 180.
  4. The region is bounded. max Z=180 at (0,20), (15,15) and every point on their joining segment.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Draw each boundary ax+by=c and retain the closed half-plane ax+by≤c; intersect all constraints, including x,y≥0.
  • [1 mark] Solving pairs of boundary equations and rejecting points violating any inequality gives vertices: (0,10), (0,20), (5,5), (15,15).
  • [1 mark] Evaluate the objective at every vertex: (0,10) → 90; (0,20) → 180; (5,5) → 60; (15,15) → 180.
  • [0.5 marks] The region is bounded. max Z=180 at (0,20), (15,15) and every point on their joining segment.

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