Mathbee CBSE Mathbee · CBSE Class 12 Maths
Class 12 Linear Programming · Mcq Single Correct1 Markscorner_point_optimization

Class 12 Maths · Linear Programming · Mcq Single Correct #48

The unbounded feasible region in the first quadrant has lower boundary D(0,8),C(2,5),B(4,3),A(9,0), and extends upwards and rightwards. Where is Z=4x+3y minimum?

✅ Step-by-Step Solution

Final Answer: Option (B): (2,5)
  1. Boundary vertex values are 24,23,25,36. All recession directions are nonnegative, so the positive objective cannot decrease along them; minimum 23 at (2,5).

Master Chapter 12: Linear Programming

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Linear Programming.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
Maximize and minimize Z=5*x + 2*y subject to x - 2*y ≤ 2; 3*x + 2*y…
Next Question →
The solution of 3x+2y>3 is:

More Practice Questions in Linear Programming

Related Questions in Linear Programming