Class 12 Matrices · Short Answer2 Marksmatrix_equality

Class 12 Maths · Matrices · Short Answer #89

Find A such that 2A−3B+5C=O, where B=\(\begin{bmatrix}-2 & 2 & 0\\3 & 1 & 4\end{bmatrix}\) and C=\(\begin{bmatrix}2 & 0 & -2\\7 & 1 & 6\end{bmatrix}\).

✅ Step-by-Step Solution

Final Answer: \(\begin{bmatrix}-8 & 3 & 5\\-13 & -1 & -9\end{bmatrix}\)

Rearrange to A=(3B−5C)/2.
Compute 3B=\(\begin{bmatrix}-6 & 6 & 0\\9 & 3 & 12\end{bmatrix}\) and 5C=\(\begin{bmatrix}10 & 0 & -10\\35 & 5 & 30\end{bmatrix}\). Subtract and divide each entry by 2.
Therefore A=\(\begin{bmatrix}-8 & 3 & 5\\-13 & -1 & -9\end{bmatrix}\).

📋 CBSE Stepwise Marking Scheme

[0.5 marks] Rearrange to A=(3B−5C)/2.
[1 mark] Compute 3B=\(\begin{bmatrix}-6 & 6 & 0\\9 & 3 & 12\end{bmatrix}\) and 5C=\(\begin{bmatrix}10 & 0 & -10\\35 & 5 & 30\end{bmatrix}\). Subtract and divide each entry by 2.
[0.5 marks] Therefore A=\(\begin{bmatrix}-8 & 3 & 5\\-13 & -1 & -9\end{bmatrix}\).

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Class 12 Maths · Matrices · Short Answer #89

✅ Step-by-Step Solution

📋 CBSE Stepwise Marking Scheme

Master Chapter 3: Matrices

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