Class 12 Matrices · Short Answer2 Marksmatrix_equality
Class 12 Maths · Matrices · Short Answer #90
For A=\(\begin{bmatrix}0 & 2\\3 & -4\end{bmatrix}\) and kA=\(\begin{bmatrix}0 & 3a\\2b & 24\end{bmatrix}\), find k,a,b.
✅ Step-by-Step Solution
Final Answer: k=−6,a=−4,b=−9
- By corresponding-entry equality, −4k=24, 2k=3a and 3k=2b.
- Solve successively: k=−6, a=2(−6)/3=−4, b=3(−6)/2=−9.
- Thus (k,a,b)=(−6,−4,−9).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] By corresponding-entry equality, −4k=24, 2k=3a and 3k=2b.
- [1 mark] Solve successively: k=−6, a=2(−6)/3=−4, b=3(−6)/2=−9.
- [0.5 marks] Thus (k,a,b)=(−6,−4,−9).
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