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Class 12 Probability · Very Long Answer5 Marksprobability_distributions

Class 12 Maths · Probability · Very Long Answer #83

Ten tickets consist of two prizes of ₹8, five of ₹4, and three of ₹2. Draw one uniformly. Find the expected prize.

✅ Step-by-Step Solution

Final Answer: P(X=2)=3/10; P(X=4)=1/2; P(X=8)=1/5. Mean=21/5.
  1. Let X be the prize amount; possible values are ₹2,₹4,₹8.
  2. The category probabilities are the ticket counts divided by 10: 3/10,5/10,2/10.
  3. The resulting distribution is P(X=2)=3/10; P(X=4)=1/2; P(X=8)=1/5. Its nonnegative masses sum to 1.
  4. E(X)=ΣxP(X=x)=(2)(3/10)+(4)(1/2)+(8)(1/5)=21/5.
  5. P(X=2)=3/10; P(X=4)=1/2; P(X=8)=1/5. Mean=21/5.

📋 CBSE Stepwise Marking Scheme

  • [1 mark] Let X be the prize amount; possible values are ₹2,₹4,₹8.
  • [1 mark] The category probabilities are the ticket counts divided by 10: 3/10,5/10,2/10.
  • [1 mark] The resulting distribution is P(X=2)=3/10; P(X=4)=1/2; P(X=8)=1/5. Its nonnegative masses sum to 1.
  • [1 mark] E(X)=ΣxP(X=x)=(2)(3/10)+(4)(1/2)+(8)(1/5)=21/5.
  • [1 mark] P(X=2)=3/10; P(X=4)=1/2; P(X=8)=1/5. Mean=21/5.

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