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Class 12 Probability · Short Answer2 Marksfinite_sample_spaces

Class 12 Maths · Probability · Short Answer #40

Choose uniformly a card numbered 1 to 100. Find P(number divisible by 6 or 8, but not 24).

✅ Step-by-Step Solution

Final Answer: 1/5
  1. Let A,B be divisibility by 6,8. Counts are ⌊100/6⌋=16, ⌊100/8⌋=12; their intersection is divisibility by lcm(6,8)=24, count 4.
  2. The union has 16+12−4=24 elements. Removing the 4 multiples of 24 leaves 20.
  3. P=20/100=1/5.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Let A,B be divisibility by 6,8. Counts are ⌊100/6⌋=16, ⌊100/8⌋=12; their intersection is divisibility by lcm(6,8)=24, count 4.
  • [1 mark] The union has 16+12−4=24 elements. Removing the 4 multiples of 24 leaves 20.
  • [0.5 marks] P=20/100=1/5.

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