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Class 12 Probability · Long Answer3 Marksindependence

Class 12 Maths · Probability · Long Answer #106

Students A,B arrive on time independently with probabilities 3/7,5/7. Find P(exactly one is on time).

✅ Step-by-Step Solution

Final Answer: 26/49
  1. The favorable disjoint events are A on time,B late and A late,B on time.
  2. By independence their probabilities are (3/7)(2/7)=6/49 and (4/7)(5/7)=20/49.
  3. Add the disjoint probabilities: 6/49+20/49=26/49.
  4. Therefore P(exactly one is on time)=26/49.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] The favorable disjoint events are A on time,B late and A late,B on time.
  • [1 mark] By independence their probabilities are (3/7)(2/7)=6/49 and (4/7)(5/7)=20/49.
  • [1 mark] Add the disjoint probabilities: 6/49+20/49=26/49.
  • [0.5 marks] Therefore P(exactly one is on time)=26/49.

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