Class 12 Probability · Short Answer2 Marksconditional_probability
Class 12 Maths · Probability · Short Answer #99
Given P(A)=3/10,P(B)=2/5,P(A∪B)=3/5, find P(B|A)+P(A|B).
✅ Step-by-Step Solution
Final Answer: 7/12
- The intersection probability is 3/10+2/5−3/5=1/10.
- P(B|A)=(1/10)/(3/10)=1/3 and P(A|B)=(1/10)/(2/5)=1/4.
- Their sum is 1/3+1/4=7/12.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The intersection probability is 3/10+2/5−3/5=1/10.
- [1 mark] P(B|A)=(1/10)/(3/10)=1/3 and P(A|B)=(1/10)/(2/5)=1/4.
- [0.5 marks] Their sum is 1/3+1/4=7/12.
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