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Class 12 Probability · Long Answer3 Marksconditional_probability

Class 12 Maths · Probability · Long Answer #54

Two children are independently equally likely to be boys or girls. Find P(both girls) given (i) youngest is a girl; (ii) at least one is a girl.

✅ Step-by-Step Solution

Final Answer: (i) 1/2; (ii) 1/3
  1. Use ordered birth sequences BB,BG,GB,GG, each of probability 1/4.
  2. Given youngest is a girl, only BG,GG remain and only GG has both girls, so probability=1/2.
  3. Given at least one girl, the possible sequences are BG,GB,GG; one is GG, so probability=1/3.
  4. The two conditional probabilities are 1/2 and 1/3, respectively.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Use ordered birth sequences BB,BG,GB,GG, each of probability 1/4.
  • [1 mark] Given youngest is a girl, only BG,GG remain and only GG has both girls, so probability=1/2.
  • [1 mark] Given at least one girl, the possible sequences are BG,GB,GG; one is GG, so probability=1/3.
  • [0.5 marks] The two conditional probabilities are 1/2 and 1/3, respectively.

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