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Class 12 Probability · Long Answer3 Marksprobability_distributions

Class 12 Maths · Probability · Long Answer #65

Roll two independent fair dice. Let X be the absolute difference of their scores. Find its distribution.

✅ Step-by-Step Solution

Final Answer: P(X=0)=1/6; P(X=1)=5/18; P(X=2)=2/9; P(X=3)=1/6; P(X=4)=1/9; P(X=5)=1/18.
  1. There are 36 equally likely ordered dice outcomes; X ranges from 0 to 5.
  2. For X=0 there are 6 doubles. For a positive difference d, there are 2(6−d) ordered pairs, giving counts 10,8,6,4,2. The probabilities are P(X=0)=1/6; P(X=1)=5/18; P(X=2)=2/9; P(X=3)=1/6; P(X=4)=1/9; P(X=5)=1/18. Their sum is 1.
  3. All masses are nonnegative and exhaust the possible values of X.
  4. P(X=0)=1/6; P(X=1)=5/18; P(X=2)=2/9; P(X=3)=1/6; P(X=4)=1/9; P(X=5)=1/18.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] There are 36 equally likely ordered dice outcomes; X ranges from 0 to 5.
  • [1 mark] For X=0 there are 6 doubles. For a positive difference d, there are 2(6−d) ordered pairs, giving counts 10,8,6,4,2. The probabilities are P(X=0)=1/6; P(X=1)=5/18; P(X=2)=2/9; P(X=3)=1/6; P(X=4)=1/9; P(X=5)=1/18. Their sum is 1.
  • [1 mark] All masses are nonnegative and exhaust the possible values of X.
  • [0.5 marks] P(X=0)=1/6; P(X=1)=5/18; P(X=2)=2/9; P(X=3)=1/6; P(X=4)=1/9; P(X=5)=1/18.

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