Class 12 Probability · Short Answer2 Marksprobability_distributions
Class 12 Maths · Probability · Short Answer #41
X has P(X=0)=k, P(X=1)=2k, P(X=2)=3k and zero elsewhere. Find k.
✅ Step-by-Step Solution
Final Answer: k=1/6
- Probabilities sum to one.
- Thus k+2k+3k=6k=1, giving k=1/6.
- The distribution is (1/6,1/3,1/2), all nonnegative, so k=1/6 is valid.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Probabilities sum to one.
- [1 mark] Thus k+2k+3k=6k=1, giving k=1/6.
- [0.5 marks] The distribution is (1/6,1/3,1/2), all nonnegative, so k=1/6 is valid.
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