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CBSE Class 12 Mathematics 2026 Supplementary Paper 65/7/3 · Q111 Marksrates_of_change

CBSE Class 12 Mathematics 2026 Supplementary Paper 65/7/3 · Question 11 (Applications Of Derivatives)

A particle has position S(t)=2t³−6t²+8. Find its velocity when the acceleration vanishes.

(A) −6 units/s
(B) 0 units/s
(C) 18 units/s
(D) 6 units/s

✅ Step-by-Step Solution

Final Answer: −6 units/s

The velocity is 6t²−12t and acceleration is 12t−12. At t=1 the velocity is −6.

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