Class 12 Relations And Functions · Mcq Single Correct1 Markstypes_of_relations
Class 12 Maths · Relations And Functions · Mcq Single Correct #19
Let \(P=\{(x,y):|x^2+y^2|=1,\ x,y\in\mathbb{R}\}\). Then \(P\) is
(A) Reflexive
(B) Symmetric
(C) Transitive
(D) Anti-symmetric
✅ Step-by-Step Solution
Final Answer: Option (B): Symmetric
Interchanging \(x\) and \(y\) preserves the equation, so the relation is symmetric. It is not reflexive: \((0,0)\notin P\); not transitive: \(1P0\) and \(0P1\) but not \(1P1\); not antisymmetric: \(1P0\) and \(0P1\).
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