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Class 12 Relations And Functions · Assertion Reason1 Markstypes_of_functions

Class 12 Maths · Relations And Functions · Assertion Reason #152

Assertion: The function \(f:\mathbb R\to\mathbb R\), \(f(x)=\begin{cases}1,&x>0\\0,&x=0\\-1,&x<0\end{cases}\), is a bijection. Reason: A bijection is a function that is both one-one and onto.

✅ Step-by-Step Solution

Final Answer: Option (D): A is false, but R is true.
  1. The sign function is not injective and has only three output values, so it is not onto R. The definition of bijection is true.

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