Class 12 Vector Algebra · Short Answer2 Marksorthogonality
Class 12 Maths · Vector Algebra · Short Answer #111
Find a unit vector perpendicular to (4,3,1) and (2,−1,2).
✅ Step-by-Step Solution
Final Answer: ±(7,−6,−10)/√185
- Compute the cross product (4,3,1)×(2,−1,2)=(7,−6,−10).
- Its norm is √(49+36+100)=√185.
- Normalize: ±(7,−6,−10)/√185; either sign is acceptable.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Compute the cross product (4,3,1)×(2,−1,2)=(7,−6,−10).
- [1 mark] Its norm is √(49+36+100)=√185.
- [0.5 marks] Normalize: ±(7,−6,−10)/√185; either sign is acceptable.
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