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Class 12 Vector Algebra · Long Answer3 Marksvector_identities

Class 12 Maths · Vector Algebra · Long Answer #67

Given |a|=1, |b|=2, |c|=3, the scalar projections of b and c onto a are equal, and b⊥c, find |3a−2b+2c|.

✅ Step-by-Step Solution

Final Answer: √61
  1. Equal scalar projections give a·b=a·c, since |a|=1. Also b·c=0.
  2. Expand the squared norm: 9|a|²+4|b|²+4|c|²−12a·b+12a·c−8b·c.
  3. The mixed terms cancel or vanish, leaving 9+16+36=61.
  4. Therefore |3a−2b+2c|=√61.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Equal scalar projections give a·b=a·c, since |a|=1. Also b·c=0.
  • [1 mark] Expand the squared norm: 9|a|²+4|b|²+4|c|²−12a·b+12a·c−8b·c.
  • [1 mark] The mixed terms cancel or vanish, leaving 9+16+36=61.
  • [0.5 marks] Therefore |3a−2b+2c|=√61.

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