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Class 12 Vector Algebra · Long Answer3 Marksdot_product_angle

Class 12 Maths · Vector Algebra · Long Answer #68

Nonzero mutually perpendicular vectors a,b,c have equal magnitudes. Prove a+b+c is equally inclined to each and find the common angle.

✅ Step-by-Step Solution

Final Answer: arccos(1/√3)
  1. Let their common magnitude be r>0 and s=a+b+c. Pairwise dot products vanish.
  2. Then |s|²=3r² and s·a=s·b=s·c=r².
  3. The cosine of each angle is r²/(r√3r)=1/√3.
  4. All three angles are arccos(1/√3), so the inclination is equal.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Let their common magnitude be r>0 and s=a+b+c. Pairwise dot products vanish.
  • [1 mark] Then |s|²=3r² and s·a=s·b=s·c=r².
  • [1 mark] The cosine of each angle is r²/(r√3r)=1/√3.
  • [0.5 marks] All three angles are arccos(1/√3), so the inclination is equal.

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