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Class 12 Vector Algebra · Long Answer3 Marksorthogonality

Class 12 Maths · Vector Algebra · Long Answer #74

Find a unit vector normal to the plane through A=(3,−1,2), B=(1,−1,−3), C=(4,−3,1).
Triangle and a normal based at A
Triangle and a normal based at A

✅ Step-by-Step Solution

Final Answer: ±(−10,−7,4)/√165
  1. Compute AB=(−2,0,−5) and AC=(1,−2,−1).
  2. Their cross product is (−10,−7,4).
  3. Its norm is √(100+49+16)=√165.
  4. The two unit normals are ±(−10,−7,4)/√165; either is a valid answer.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Compute AB=(−2,0,−5) and AC=(1,−2,−1).
  • [1 mark] Their cross product is (−10,−7,4).
  • [1 mark] Its norm is √(100+49+16)=√165.
  • [0.5 marks] The two unit normals are ±(−10,−7,4)/√165; either is a valid answer.

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