Class 12 Vector Algebra · Long Answer3 Markscross_product_area
Class 12 Maths · Vector Algebra · Long Answer #75
Find the area of parallelogram ABCD with AB=(3,1,4), AC=(4,0,5).
✅ Step-by-Step Solution
Final Answer: √42
- The second adjacent side is AD=AC−AB=(1,−1,1).
- Compute AB×AD=(5,1,−4).
- Its squared norm is 25+1+16=42.
- Therefore the parallelogram area is √42 square units.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The second adjacent side is AD=AC−AB=(1,−1,1).
- [1 mark] Compute AB×AD=(5,1,−4).
- [1 mark] Its squared norm is 25+1+16=42.
- [0.5 marks] Therefore the parallelogram area is √42 square units.
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