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Class 12 Vector Algebra · Long Answer3 Marksvector_projection

Class 12 Maths · Vector Algebra · Long Answer #76

For a=(2,−1,−2), b=(7,2,−3), express b=b₁+b₂ with b₁ parallel to a and b₂ perpendicular to a.

✅ Step-by-Step Solution

Final Answer: b₁=(4,−2,−4), b₂=(3,4,1)
  1. Use b₁=[(b·a)/(a·a)]a.
  2. Compute b·a=14−2+6=18 and a·a=9; hence b₁=2a=(4,−2,−4).
  3. Then b₂=b−b₁=(3,4,1), and b₂·a=6−4−2=0.
  4. Thus b=(4,−2,−4)+(3,4,1), with the required parallel and perpendicular components.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] Use b₁=[(b·a)/(a·a)]a.
  • [1 mark] Compute b·a=14−2+6=18 and a·a=9; hence b₁=2a=(4,−2,−4).
  • [1 mark] Then b₂=b−b₁=(3,4,1), and b₂·a=6−4−2=0.
  • [0.5 marks] Thus b=(4,−2,−4)+(3,4,1), with the required parallel and perpendicular components.

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